∗
∗
† ‡
†
‡
(apu)n ∗ )
(apu)n
u2x (apu)n u2x
vx = 0 f = anx = bnx
∗)
(apuv)n
vx
x
y
λx − y;
λ1 λ2 . . . λn ,
(λax − ay )n = f · {λn + a1 λn−1 + a2 λn−2 + . . . an } = 0. λκ λκ ux − uy = 0. λκ (λκ ax − ay )n = 0. λκ (ax uy − ux ay )n = (auv)n = 0, (auv)n
u
v
v
f λnκ (−1)κ
! " n f y κ = f aκ . κ
aκ
λκ (−1)κ aκ =
f
#
λ1 λ2 . . . λκ .
n α1,x α2,x . . . αn,x .
f = α1,x α2,x . . . αn,x ; (aακ u)n = 0.
v
f
λκ λκ ux − uy = 0 ακ λκ ακ,x − ακ,y = 0, λκ
λκ =
(−1)κ aκ =
ακ,y . ακ,x
# α1,y α2,y ακ,y ... . α1,x α2,x ακ,x
λκ sν = λν1 + λν2 . . . λνn aκ sn = (−1)n an1 + (−1)n−1 an−2 a2 . . . . 1 aκ ! " κ n f aκ = (−1) fy κ κ sn f
fn
fy ν
n $ f sn = np % n α1,y αn2,y αnκ,y n + n ... n =f · αn1,x α2,x ακ,x
f p = nn−1 fyn − nn−1 f fyn−2 fy2 · · · f2 p = pny .
p
n
y
y
x n−κ f n sκ = npκ . y px
(apu)n = 0. f x
f
fy (af u)n fy
(af u)n
f u
fy
u2x (apu)n f
(apu)n
u2x # = un" um x sn aκ
(apu)n
u2x
(af u)n , (apu)n (af u)n = Aunx + Bf, B f, (abu), (af u), bx . (apu)n
u2x
u2x
#
# = un" um x
ux m = 1.
(#xy)n = 0 # #
ux
ux ϑ = un−1 ϑ
un" = ux un−1 . ϑ u
x &y
y
0 = (#x& uv)n = (u" vx − v" ux )n ! " κ n = (−1) (u" vx )n−κ (v" ux )κ , κ κ=0 κ=n #
#vxn
u &v
! " n = −ux v" (−1) (u" vx )n−κ (v" ux )κ−1 , κ κ=1 κ=n #
κ
m=2
v" (#xy)n−1 # #
u2x ϑ = un−2 ϑ
u2x
un" = u2x un−2 ϑ u
v nun−1 v" = 2ux vx un−2 + (n − 2)u2x un−3 vϑ . " ϑ ϑ x &y
u
v # ϑ = un−2 ϑ
x &y
ux
un" = u2x un−2 . ϑ u
v nun−1 v" = vx un−1 + (n − 1)ux vϑ un−2 " ϑ ϑ x &y
u
0 = vx (ϑxy)n−1 . ϑ
ux
u2x
#
m = 3, 4, 5, . . . # um x um−1 (#xy)n−m+1 = 0. " #
um x ϑ = un−m ϑ
n−m un" = um . x uϑ
u
x &y
! " ! " n − m m n−m−1 n n−1 (#xy) = ux uϑ (ϑxy), u ! 1 " ! 1" n − m m n−m−2 n n−2 ux uϑ (ϑxy)2 , u" (#xy)2 = 2 2 ! " ! " 3 n−3 n − m m n−m−3 3 u (#xy) = ux uϑ (ϑxy)3 , 1 " 3 · · · · · · ·!· · · · · " ! " n−m m n m n−m = ux uϑ (ϑxy)n−m , u" (#xy) n − m n−m ! " n um−1 (#xy)n−m+1 = 0, n−m+1 " # um−1 x ϑ = un−m+1 ϑ
un" = um−1 un−m+1 . x ϑ x &y !
u
" ! " n − m + 1 m−1 n−m n n−1 (#xy) = ux uϑ (ϑxy), u 1 ! " ! 1" n − m + 1 m−1 n−m−1 n n−2 ux uϑ (ϑxy)2 , u" (#xy)2 = 2 2 · · · · · · · ·! ···· " ! " n − m + 1 m−1 n m n−m = ux uϑ (ϑxy)n−m , u" (#xy) n − m n − m ! " ! " n − m + 1 m−1 n n−m+1 (#xy) = u (ϑxy)n−m+1 , um−1 n−m+1 x n−m+1 " (ϑxy)n−m+1 = 0. ϑ
ux
#
um−2 (#xy)n−m+2 = 0, " um−2 (#xy)n−m+1 (#yz) = 0, " um−2 (#xy)n−m+1 (#zx) = 0, "
um x
uz (#xy) + ux (#yz) + uy (#zx) = u" (xyz) #
u2x (#xy)n = 0, (#xy)n−1 (#yz) = 0, (#xy)n−1 (#zx) = 0. sn
a
(apu)n .
κ=n # κ=0
an−κ sκ = 0,
xn + a1 xn−1 + a2 xn−2 + · · · an = (x − λ1 )(x − λ2 ) · · · (x − λn ) aκ sn
n
nsn =
κ=n # κ=1
κaκ
∂sn ∂aκ
g0 g1 g2 · · · g0 = −1
∂sn . ∂aκ
κ=n # κ=0
an−κ gκ = 0.
∂sn = ngµ . ∂an−µ ∂sn = −n ∂an µ = 0 µ = 1, 2, 3, . . . µ
κ>0 ∂sn−κ = (n − κ)gµ−κ ∂an−µ
sµ =
κ=µ # κ=1
κ=n # κ=0
an−µ sn−κ
κaκ gµ−κ .
aκ sn−κ
κ≤µ κ=µ # κ=0
aκ
∂sn−κ + sµ = 0, ∂an−µ
∂sn−κ ∂an−µ
sµ
κ=µ κ=µ # # ∂sn + (n − κ)gµ−κ aκ + κaκ gµ−κ = 0 ∂sn−µ κ=1 κ=1 κ=µ # ∂sn +n gµ−κ aκ = 0. ∂sn−µ κ=1
n
κ=µ # κ=0
gµ−κ aκ = 0,
∂sn = ngµ . ∂an−µ
dsκ
W =
κ=n # λ=n # κ=1 λ=1
daκ
κaκ gn−κ−λ+1 daλ
λ κ sn−λ+1 =
κ=n # κ=1
dsn−κ+1 =
λ=n # λ=1
κaκ gn−κ−λ+1 , λ=n
# ∂sn−κ+1 daκ = (n − κ + 1) gn−κ−λ+1 daλ , ∂aκ λ=1
W κ=n # κ=1
κ=n # κ=1
κ=n #! κ=1
κ aκ dsn−κ+1 , n−κ+1
κ aκ dsn−κ+1 − sn−κ+1 daκ n−κ+1
κ=n−1 # ! κ=1
sn−κ+1 daκ
κ+1 aκ+1 dsn−κ − sn−κ daκ+1 n−κ
"
"
= 0,
= 0.
aκ
sκ
f
! " n κ n−κ f aκ = (−1) , a a κ y x κ
f n sn−κ = npn−κ pκ y x.
y
z
dy = z
' n ( κ−1 f daκ = (−1)κ κ , κay az an−κ x n κ f dsn−κ = n(n − κ)pn−κ−1 p p z y x. aκ , sn−κ , daκ , dsn−κ
κ=n−1 # ! κ=1
κ=n # κ=0
an−κ sκ = 0,
κ+1 aκ+1 dsn−κ − sn−κ daκ+1 n−κ
"
=0
! " n κ n−κ n−κ κ ay ax py px = 0, κ κ=0 ! " κ=n−1 # )κ + 1 n κ+1 (−1) an−κ−1 (n − κ)pn−κ−1 pz pκ = aκ+1 y x y x κ + 1 n − κ κ=0 ! " * n n−κ κ κ+1 κ n−κ−1 −py px (−1) (κ + 1)ay az ax κ+1 ! " κ=n−1 # n = (ay pz − py az ) (−1)κ+1 (κ + 1) aκ+1 an−1−κ pn−1−κ pκ y x y x κ + 1 κ=0 ! " κ=n−1 # n−1 = −n(ay pz − py az ) (−1)κ (ay px )κ (ax py )n−1−κ κ κ=0 κ=n #
(−1)κ
0
(ay px − py ax )n = 0,
(ay pz − py az )(ay px − py ax )n−1 = 0. y
z
(az px − pz ax )(ay px − py ax )n−1 = 0. (apu)n u2x (af u)n pny fy f f =0
x fy
f
(apu)
n
f
fy n (af u)n x x
(af u)n
u2x (af u)n = Au2x + Bf
(af u)n (A + Cf )u2x + (B − Cu2x )f. (af u)n f f, (abu), (af u), bx (af u)n
(af u)n
(af u)n (af u)n = Au2x + Bf. B B = Cu2x + D (af u)n (af u)n = (A + Cf )u2x + Du2x , D f, (abu), (af u), bx .
(af u)n
(af u)n (af u)n = Au2x + Bf
+ , 1 (abu) ((af u)bx )n−1 − ((bf u)ax )n−1 2 κ=n−2 # 1 n−2−κ κ = (abu)((af u)bx − (bf u)ax ) {(af u)bx } {(bf u)ax } 2 κ=0
(af u)n = (abu)(af u)n−1 bn−1 = x
=
κ=n−2 # 1 n−2−κ κ (abu) {f (abu) − ux (abf )} ((af u)bx ) ((bf u)ax ) . 2 κ=0
κ=n−2 # 1 (abu)2 ((af u)bx )n−2−κ ((bf u)ax )κ 2 κ=0
κ=n−2 # 1 n−2−κ κ (abu)(abf ) ((af u)bx ) ((bf u)ax ) 2 κ=0
ux L = −2Aux.
K=
#
(abc)2 (af u)κ (bf u)λ (cf u)µ an−2−κ bn−2−λ cn−2−µ x x x κ, λ, µ κ + λ + µ = n − 2. ux (abc) = ax (bcu) + bx (cau) + cx (abu), ux K a, b, c f
Kux = 3(abc)(abu)
# (af u)κ (bf u)λ (cf u)µ an−2−κ bn−2−λ cn−2−µ . x x x
µ=0
3L
µ=ν+1
Kux − 3L # bn−2−λ cn−2−ν , = 3(abc)(abu)(cf u) (af u)κ (bf u)λ (cf u)ν an−2−κ x x x κ, λ, ν
κ+λ+ν =n−3 a, b, c
= (abc) = 0.
-
Kux − 3L ((abu)(cf u) + (bcu)(af u) + (cau)(bf u)) # κ · (af u) (bf u)λ (cf u)ν an−2−κ bn−2−λ cn−2−ν x x x L=
1 Kux , 3
1 A=− K 6
=−
1# (abc)2 (af u)κ (bf u)λ (cf u)µ an−2−κ bn−2−λ cn−2−µ . x x x 6
B=
κ=n−2 # 1 n−2−κ κ (abu)2 ((af u)bx ) ((bf u)ax ) 2 κ=0
B = Cu2x + D D f, (abu), (af u), bx
xn + y n = − y n−1 ) = n(x n−1
(y + (x − y))n n−1 n (y + (x − y))
+ (x − (x − y))n , n−1 − n (x − (x − y))
" ( n ' n−κ y n(x −y )= + (−1)κ xn−κ (x − y)κ−1 , κ κ=2 κ=n−2 κ=n # # !n" ' ( y n−κ + (−1)κ xn−κ (x − y)κ−2 , xn−2−κ y κ = n κ κ=0 κ=2 κ=n # !n − 1" ' ( y n−κ + (−1)κ xn−κ (x − y)κ−1 , 2n(xn−1 − y n−1 ) = n κ−1 κ=2 ! " κ=n # n ( ' = κ y n−κ + (−1)κ xn−κ (x − y)κ−1 , κ κ=2 κ=n # !n" ( ' 0= (κ − 2) y n−κ + (−1)κ xn−κ (x − y)κ−3 . κ κ=3 n−1
κ=n #!
n−1
bx (af u),
x
x−y
(abu)
2nB
= (abu)
2
κ=n #! κ=2
2
y
ax (bf u)
f (abu) − ux (abf )
(abu)2 (abf )
" ( n ' (ax (bf u))n−κ + (−1)κ (bx (af u))n−κ κ
0 = (abu)2 ux (abf )
κ=3
a
κ−2
(f (abu) − ux (abf )) , " ( ' n (κ − 2) (ax (bf u))n−κ + (−1)κ (bx (af u))n−κ κ
κ=n #!
κ−3
(f (abu) − ux (abf ))
.
b
! " n κ−2 nB = (abu) (−1) , (ax (bf u))n−κ + (−1)κ (bx (af u))n−κ (f (abu) − ux (abf )) κ κ=2 ! " κ=n # n 0 = (abu)2 ux (abf ) (−1)κ (κ − 2)(bx (af u))n−κ κ κ=3 2
κ=n #
κ
(f (abu) − ux (abf ))κ−3 .
nB
0
! " . n n−κ f (abu)κ−2 = (abu) (−1) (bx (af u)) κ κ=2 ! " λ=κ−2 / # κ−2 + (−1)λ (f (abu))κ−2−λ (ux (abf ))λ , λ λ=1 ! " ! " κ=n # λ=κ−2 # n κ−2 n−κ = (abu)2 ux (abf ) (−1)κ+λ (κ − 2) (bx (af u)) κ λ − 1 κ=3 2
κ=n #
κ
λ=1
= (abu)2
κ=2
nB
(f (abu))κ−2−λ (ux (abf ))λ−1 " ! "! κ−2 n n−κ κ−2−λ (−1)κ+λ (f (abu)) λ (bx (af u)) λ κ
κ=n # λ=κ−2 # λ=1
λ
(ux (abf )) , κ=n ! " # n n−κ κ−2 (−1)κ (f (abu)) (bx (af u)) κ κ=2 ! "! " κ=n # λ=κ−2 # = (abu)2 κ−2 2 2 κ+λ n −ux(abf ) (−1) (λ − 1) κ λ κ=2 λ=2 n−κ κ−2−λ λ−2 (bx (af u)) (f (abu)) (ux (abf )) . B = Cu2x + D,
nC = −(abu)2 (abf )2
nD =
κ=n # λ=κ−4 #
(−1)κ+λ
κ=4
κ=n #
λ=0
(−1)κ
κ=2
! "! " n κ−2 (λ + 1) κ λ+2 n−κ
(bx (af u))
κ−4−λ
(f (abu))
λ
(ux (abf )) ,
! " n n−κ κ−2 κ f (f (abu)) . (bx (af u)) κ
(af u)n = (A + Cf )u2x + Df, n # 2 2 − u (abc) bn−2−λ cn−2−µ (af u)κ (bf u)λ (cf u)µ an−2−κ x x x x 6 ! "! " κ=n λ=κ−4 # # n κ−2 (−1)κ+λ (λ + 1) −f u2x (abu)2 (abf )2 κ λ+2 κ=4 λ=0 n(af u)n = n−κ κ−4−λ λ (f (abu)) (ux (abf )) (bx (af u)) ! " κ=n # n n−κ κ−2 κ (−1)κ f (f (abu)) . (bx (af u)) +f κ κ=2
q=
qyn
=
nfyn
! " n κ−2 −f (−1) fyn−κ fyκ ; f κ κ=2 κ=n #
κ
# n − (abc)2 bn−2−λ cn−2−µ (af u)κ (bf u)λ (cf u)µ an−2−κ x x x 6 ! "! " κ=n λ=κ−4 # # n κ−2 (aqu)n = u2x −f (abu)2 (abf )2 (−1)κ+λ (λ + 1) κ λ+2 κ=0 λ=0 n−κ κ−4−λ λ (f (abu)) (ux (abf )) . (bx (af u)) u2x pny
qyn
n − 1 n−2 f fy fy 2 , nn−1 fyn − nn−1 ! " 2 n nfyn − f fyn−2 fy2 , 2 f2 pny − nn−2 qyn pny = nn−2 qyn + f 2 ryn . f (apu)n = nn−2 (aqu)n + f 2 (aru)n ; (aru)n
u2x (ay rx − ry ax )n = 0,
(ay rx − ry ax )n−1 (aru) = 0.
(n ' ' (n 0 = (abu)rx − (rbu)ax = (abr)ux + bx (aru) , ' (n−1 ' (n−1 0 = (abu)rx − (rbu)ax (abr)ux = (abr)ux + bx (aru) (abr)ux , n−1
0 = bnx (aru)n + n (bx (aru)) ux (abr) ! κ=n # n" n−κ κ−2 + u2x (abr)2 (ux (abr)) , (bx (aru)) κ κ=2
0 = n (bx (aru))
n−1
ux (abr) κ=n # !n − 1" n−κ κ−2 +u2x (abr)2 n (bx (aru)) (ux (abr)) , κ − 1 κ=2 κ=n # !n" n−κ κ−2 n 2 2 f (aru) = ux (abr) (ux (abr)) . (κ − 1) (bx (aru)) κ κ=2 (aqu)n
(aru)n
n# − (af u)κ (bf u)λ (cf u)µ an−2−κ bn−2−λ cn−2−µ x x x 6 ! "! " κ=n λ=κ−4 # # n κ−2 (−1)κ+λ (λ + 1) −f (abu)2 (abf )2 κ λ+2 κ=4 λ=0 (apu)n = u2x (bx (af u))n−κ (f (abu))κ−4−λ (ux (abf ) λ ! " κ=n # n 2 (κ − 1) (bx (aru))n−κ (ux (abr))κ−2 . +f (abr) κ κ=2 C C K
C
ξ K
x f
#
fy