multipliers on banach spaces of functions on a locally compact abelian

Apr 18, 2007 - Let G be a locally compact Abelian (LCA) group with unit element 0 = 0G. ...... R. E. Edwards, Functional analysis: theory and applications (Holt, ...
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J. London Math. Soc. (2) 75 (2007) 369–390

e 2007 London Mathematical Society

C

doi:10.1112/jlms/jdm002

MULTIPLIERS ON BANACH SPACES OF FUNCTIONS ON A LOCALLY COMPACT ABELIAN GROUP VIOLETA PETKOVA Abstract Let E be a Banach space of functions on a locally compact Abelian group G satisfying certain conditions. It has  been proved that for every bounded operator M on E commuting with translations there exists hM ∈ L∞ (G E) f = hM f˜ ∀f ∈ Cc (G), where G  is a suitable subset of the group of the continuous morphisms such that M E  from G into C∗ and g is a generalized Fourier transform of g defined on G E.

1. Introduction  the Let G be a locally compact Abelian (LCA) group with unit element 0 = 0G . Denote by G dual group of G, that is, the set of continuous morphisms χ : G −→ T, where T denotes the unit  respectively, circle. Throughout the paper, dx and dχ denote the Haar measures on G and G, normalized so that  F : L2 (G) −→ L2 (G), the Fourier transform, is an isometry. Recall that for f ∈ L1 (G), F(f ) is defined by   F(f )(χ) = f (x)χ(−x) dx ∀χ ∈ G G

 we have a.e. and if g = F(f ) ∈ L (G) 1

f (x) = F −1 (g)(x) =

  G

g(χ)χ(x) dχ.

Sometimes we will write fˆ instead of Ff . The reader may find the basic properties of the LCA groups in [18]. Denote by Cc (G) the space of continuous complex-valued functions on G with compact support and denote by CK (G) the space of functions in Cc (G) with support included in a compact K ⊂ G. For f ∈ Cc (G), set f ∞ = supx∈G |f (x)|, so that the spaces CK (G) are Banach algebras with respect to the norm  · ∞ . We have Cc (G) = lim CK (G), and we equip → Cc (G) with the locally convex topology τ associated to this inductive limit. It is well known that a sequence (fn )n1 of elements of Cc (G) converges to zero with respect to τ if and only if the following two conditions hold: (1)  limn→+∞ fn ∞ = 0; (2) n∈N supp(fn ) is relatively compact in G. It is also well known that a linear map φ from Cc (G) into a locally convex space E is continuous if and only if limn→+∞ φ(fn ) = 0 for every sequence (fn )n1 which converges to 0 in Cc (G) with respect to τ . In other terms, every sequentially continuous linear map from Cc (G) into a locally convex space is continuous [1, Chapter 7; 4, 5]. Let L1loc (G) be the space of all measurable complex-valued functions f on G such that f |K is integrable with respect to the Haar measure on every compact set K ⊂ G. For x ∈ G, let Sx

Received 6 January 2006; published online 18 April 2007. 2000 Mathematics Subject Classification 43A22, 43A25.

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V. PETKOVA

be the operator defined on

L1loc (G)

by

Sx f (y) = f (y − x)

a.e.

 denote by Γχ the operator f −→ χf on L1 (G). Let E ⊂ L1 (G) be a Banach For χ ∈ G, loc loc space, and assume that the identity map i : E −→ L1loc (G) is continuous. It follows from the closed graph theorem that if Sx (E) ⊂ E for x ∈ G, the operator Sx is bounded from E into  the operator Γχ is bounded from E into E. We will be E. Likewise, if Γχ (E) ⊂ E for χ ∈ G, interested in Banach spaces E satisfying the following conditions: (H1) Cc (G) ⊂ E ⊂ L1loc (G), with continuous inclusions, and Cc (G) is dense in E; (H2) for every x ∈ G, Sx (E) ⊂ E and supx∈K Sx  < +∞ for every compact set K ⊂ G;  Γχ (E) ⊂ E and sup  Γχ  < +∞. (H3) for every χ ∈ G, χ∈G Set |||f ||| = supχ∈G Γχ f  for f ∈ E. The norm ||| · ||| is equivalent to the norm of E and, without loss of generality, we can consider below that Γχ is an isometry on E for every  From now, Sx for x ∈ G (respectively, Γχ for χ ∈ G)  will denote the restriction of χ ∈ G. Sx (respectively, Γχ ) on E. Definition 1.

A multiplier on E is a bounded linear operator M : E −→ E

such that Sx M = M S x

∀x ∈ G.

The algebra of the multipliers on E is denoted by M(E). Let B(E) be the closed algebra generated by {Sx }x∈G . Given a commutative Banach algebra A, we will denote by A the set of characters of A. Denote by σ({Sx }x∈G ) the joint spectrum of {Sx }x∈G defined by  σ({Sx }x∈G ) = {(γ(Sx ))x∈G , γ ∈ B(E)}. In the particular case E = Lp (G) for 1  p < ∞, it is well known [15] (see [12] for G = R)  such that that for M ∈ M(E), there exists h ∈ L∞ (G) f = hf M

∀f ∈ Cc (G).

(1.1)

The function h is called the symbol of M . The aim of this paper is to obtain a representation theorem analogous to (1.1) for multipliers on a general Banach space E satisfying only hypotheses (H1), (H2) and (H3). We are motivated by a result concerning the multipliers on E = L2ω (R) (see [16]), where ω is a measurable non-negative function on R. Let I = [− ln ρ(S−1 ), ln ρ(S1 )]. For a ∈ I and for f ∈ E, set (f )a (t) = eat f (t) a.e. for f ∈ E, and set Ω = {z ∈ C | Im z ∈ I}. We have the following result. Theorem 1 [16]. Let E = L2ω (R) and suppose that Sx is bounded on E for every x ∈ R. Let M ∈ M(E). (i) We have (M f )a ∈ L2 (R), for f ∈ Cc∞ (R) and a ∈ I. (ii) For a ∈ I, there exists a function ha ∈ L∞ (R) such that   (M f )a (t) = ha (t)(f )a (t)

∀f ∈ Cc∞ (R) a.e.

Moreover, there exists C > 0 such that ha ∞  CM  for every a ∈ I. ◦

(iii) If ρ(S1 ) > 1/ρ(S−1 ), there exists a function h ∈ H∞ (Ω) such that f = hf˜ M

∀f ∈ Cc∞ (R), ◦

  f (x + ia) = (M where M f )a (x), and f˜(x + ia) = (f )a (x), for x + ia ∈ Ω.

MULTIPLIERS ON BANACH SPACES

371

Here, the Fourier transform of M f and the symbol of M are defined on a strip Ω ⊂ C isomorphic to R × [− ln ρ(S−1 ), ln ρ(S1 )]. The situation when G = Z and E is a Banach space satisfying (H1), (H2) and (H3) has been considered by  the author in [17]. Denote by F (Z) the set of the finite sequences on Z. Set formally u ˜(z) = n∈Z un z n for u = (un )n∈Z ∈ CZ , and it ˜(reit ) for r  0 and t ∈ R. Denote by S the shift operator S1 and denote by set u (r) (e ) = u spec(S) the spectrum of S considered as an operator on E. Theorem 2 [17]. Let M ∈ M(E). The following properties hold: (i) spec(S) = {z ∈ C, 1/ρ(S −1 )  |z|  ρ(S)}; ∞ −1   := M  (ii) set M (e0 ) for M ∈ M(E). Then M ), ρ(S)] and (r) ∈ L (T) for r ∈ [1/ρ(S  M(r) ∞  M ; ◦  ∈ H∞ (spec(S)) and (iii) if 1/ρ(S −1 ) < ρ(S), then M u = M u M ˜

∀u ∈ F (Z).

In this case the Fourier transform of M f and the symbol of M are defined on the annulus spec(S) ≈ T × [1/ρ(S −1 ), ρ(S)].  be the set of the continuous morphisms from G Now let G be a general LCA group. Let G ∗  + into C and let G be the set of the continuous morphisms from G into R+ = (0, +∞). We  with the topology characterized by uniform convergence on every compact subset. equip G  the integral Notice that for f ∈ Cc (G) and θ ∈ G,  f (x)θ(x)−1 dx G

  We observe that f˜|  = fˆ is well defined. For f ∈ Cc (G), set f˜(θ) = G f (x)θ(x)−1 dx for θ ∈ G. G ˜  and f is a ‘generalized Fourier transform’ of f defined on G.   The first problem is to find a subset G E of G such that for every M ∈ M(E) and for −1 2  every f ∈ Cc (G) the function (M f )θ is in L (G) for θ ∈ G E . Then we will be able to define −1 naturally the Fourier transform of (M f )θ . The difficulty here is that we have very little information about M f . Taking into account the arguments from [16, 17], it is natural to consider  ˜  ∀f ∈ Cc (G)}, G E = {θ ∈ G | |f (θ)|  Mf  where Mf ∈ M(E) is the convolution operator g −→ f ∗ g on E (see the beginning of Section 2). Notice that if G is a compact group, then the range of |θ| is the trivial compact subgroup of    R+ for every θ ∈ G E , and so GE = G.    Recall that a domain X of Cn is a Reinhardt domain It is obvious that χGE = GE for χ ∈ G. −1 if Y (Y(X)) = X, where Y : Cn (z1 , . . . , zn ) −→ (|z1 |, . . . , |zn |) ∈ (R+ )n . We observe that if (x1 , . . . , xn ) ∈ Gn are ‘independent’, in the sense that the system χ(xi ) = i ,  for every ( 1 , . . . , n ) ∈ Tn , then the set 1  i  n, has a solution χ in G  {(θ(x1 ), . . . , θ(xn )), θ ∈ G E}  + +    is a Reinhardt domain. Set G E = GE ∩ G . It is clear that if θ ∈ GE , then |θ| : G x −→ |θ(x)|  + +   belongs to G E . Trivially we have GE = GE G. We prove in Section 2 the following crucial facts.

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Theorem 3. Let E be a Banach space satisfying conditions (H1), (H2) and (H3).  + (i) The set G E is non-empty, compact and logarithmically convex. (ii) We have

 G E =

 | |θ(x)−1 |  sup |η(x)−1 | θ∈G

∀x ∈ G .

 η∈G E

(1.2)

We recall that a set X is said to be logarithmically convex if xt y 1−t ∈ X for every x, y ∈ X ∀t ∈ [0, 1]. Sometimes we will write log-convex instead of logarithmically convex. If G is a  discrete or a compact group, we will see that G E satisfies the following property: −1   G (1.3) |  ρ(Sx ) ∀x ∈ G}. E = {θ ∈ G | |θ(x) We conjecture that property (1.3) holds for a general LCA group. We will establish a   homeomorphism between G E and A(G), where A(G) is the closed algebra generated by  is non-empty. Let U be an open subset of C. A function {Mφ }φ∈Cc (G) . We will see that A(E)  Π : U λ −→ Π(λ) ∈ G will be said to be analytic on U if, for every x ∈ G, the function U λ −→ Π(λ)(x) ∈ C  +  is analytic on U . Denote by d the discrete measure on G E and by m the Haar measure on G. We obtain the following general result. Theorem 4. Let E be a Banach space satisfying conditions (H1), (H2) and (H3).  + −1  ∈ L2 (G). Set for δ ∈ G (i) Let M ∈ M(E) and θ ∈ G E . For every f ∈ Cc (G), (M f )θ E,  for almost every χ ∈ G,  f (δχ) = (M M f )δ −1 (χ).  Then there exists a function hM ∈ L∞ (G E , d ⊗ m) such that we have  (M f ) = hM f˜

∀f ∈ Cc (G)

and hM ∞  CM , where C is a constant independent of M.  (ii) Let U be an open subset of Cp . Let Π : U −→ G E be an analytic function. There exists ∞  ∞  a function HM,Π ∈ L (G, H (U )) such that, for λ ∈ U, for almost every χ ∈ G, f (Π(λ)χ) = HM,Π (χ)(λ)f˜(Π(λ)χ) M

∀f ∈ Cc (G).

Now we turn to some interpretations of this theorem. Set L = {z ∈ C | Re z ∈ [0, 1]}. Fix φ  + and ψ ∈ G E . Suppose that φ = ψ. The function Π : L λ −→ φλ ψ 1−λ ◦

is analytic on L. Set Ωφ,ψ = Π(L).   Since G E is log-convex, Π(L) ⊂ GE . It is clear that Ωφ,ψ is isomorphic to L. We see that for θ = φλ ψ 1−λ ∈ Ωφ,ψ , we get the representation φ(x) Re λ 1−Re λ ∀x ∈ G. θ(x) = φ(x) ψ(x) exp iIm λ ln ψ(x) Introduce the morphism φ(x) ∈T γ : G x −→ exp i ln ψ(x)

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and set  | χ(x) = (γ(x))t γ R = {χ ∈ G

∀x ∈ G for some t ∈ R}.

Denote by Sφ,ψ the convex set defined by

 + t 1−t Sφ,ψ = η ∈ G E | η(x) = φ(x) ψ(x)

 ∀x ∈ G for some t ∈ [0, 1] .

Notice that Ωφ,ψ is isomorphic to Sφ,ψ × γ R . Observe that Theorem 4 (ii) gives some analytic  +   symbol for M ∈ M(E) as soon as G E is not a singleton even if GE has an empty interior in G. Now we discuss some examples. Example 1.

 G = Z. Then every φ ∈ G E is of the form φ : Z n −→ z n ∈ C,

where z ∈ C and 1/ρ(S −1 )  |z|  ρ(S). If ρ(S) > 1/ρ(S −1 ), we can choose φ and ψ so that ∀n ∈ Z,

φ(n) = ρ(S)n ψ(n) = ρ(S

−1 −n

)

∀n ∈ Z.

Observe that the set Sφ,ψ is isomorphic to the segment [1/ρ(S −1 ), ρ(S)] and  = T. γR ≈ Z So we obtain

Ωφ,ψ ≈

z∈C|

1  |z|  ρ(S) ρ(S −1 )

and Theorem 4 gives exactly the result of [17]. Example 2. G = Zk . Set ej = (ej,1 , . . . , ej,k ), with ej,i = 0 for i = j, and ej,j = 1. Define Sj = Sej . It follows from (1.2) that k ≈ σ(S , . . . ., S ). Z 1 k E k has the form φ = φ , where z = (z , . . . , z ) ∈ C∗k and φ is defined on Zk Each φ ∈ Z z 1 k z E by the formula φz (n1 , . . . , nk ) = z1n1 . . . zknk . In other terms if we set z n = z1n1 . . . zknk for k has the form φ = φ , where z = (z1 , . . . , zk ) ∈ Ck and n = (n1 , . . . , nk ) ∈ Zk , each φ ∈ Z z E n k ∗k φz (n) = z for n ∈ Z for some z ∈ C . Set k }. FE = {z ∈ C∗k |φz ∈ Z E

Notice that FE satisfies the following two properties. (1) We have (z1 eiθ1 , . . . , zk eiθk ) ∈ FE for every (z1 , . . . , zk ) ∈ FE and every (θ1 , . . . , θk ) ∈ Rk. (2) The set {(log |z1 |, . . . , log |zk |)}(z1 ,...,zk )∈FE is convex. ◦





In particular FE is a log-convex Reinhardt domain if FE = ∅. Assume that FE = ∅ and set ◦ ◦ k is analytic. It follows from Theorem 4 that there Π(z) = φz for z ∈ FE . Then Π : FE −→ Z E ◦ k , H∞ (FE )) satisfying, for each u ∈ F (Zk ) and exists for M ∈ M(E) a function HM,Π ∈ L∞ (Z k , for almost every χ ∈ Z u(φz χ) = HM,Π (χ)(z)˜ u(φz χ) M



∀z ∈ FE .

k for which the above formula holds. Let δ ∈ Tk be such that Now choose χ = (χ1 , . . . , χk ) ∈ Z χ = φδ . Define θM : FE z −→ HM,Π (χ)(zδ −1 ) ∈ C,

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V. PETKOVA ◦

where zδ −1 = (z1 δ1−1 , . . . , zk δk−1 ). Then θM ∈ H∞ (FE ). Obviously, we have φzδ = φz φδ for every z ∈ C∗k . We obtain for u ∈ F (Zk ) for z ∈ FE u(φzδ−1 φδ ) = θM (z)˜ u(φz ) = M u(φzδ−1 φδ ) = θM (z)˜ u(φz ). M Thus we have the following result. Let E be a Banach space of sequences on Zk satisfying (H1), (H2) and ◦ ◦ ∞ k = ∅. Then, for M ∈ M(E), there exists θ (H3). Suppose that Z M ∈ H (FE ) such that for E f ∈ F (Zk ) Corollary 1.



f (φz ) = θM (z)f˜ (φz ) ∀z ∈ FE . M Example 3.

Define E : C∗k

k is of the form G = Rk . Every element of R

ψa : x −→ e−ia,x for some a ∈ C∗k . k and note that E −1 (ψ) ∈ C∗k ∀ψ ∈ R k .

a −→ ψa ∈ R E E ◦

k = ∅. Set Suppose that R E

 UE = E

−1







 k+ ≈ Rk + iR E .

k R E



 k+ We recall that the set R E is log-convex. Notice that when k = 1, UE is a strip of C. Let k . Π : UE a −→ ψa ∈ R E For every x ∈ Rk , the function a −→ Π(a)(x) = e−ia,x is obviously analytic on UE . Fix M ∈ M(E). Applying Theorem 4 we get, for almost every k , χ∈R f (ψa χ) = HM,Π (χ)(a)f˜(ψa ) ∀a ∈ UE , M k , H∞ (UE )). Fix χ ∈ R k such that the above formula holds. Let δ ∈ Rk where HM,Π ∈ L∞ (R be such that χ = ψδ . We have f (ψaδ−1 ψδ ) = HM,Π (ψδ )(a)f˜(ψaδ−1 ψδ ) ∀a ∈ UE ∀f ∈ Cc (Rk ). M We obtain f (ψa ) = HM,Π (ψδ )(a)f˜(ψa ) M

∀a ∈ UE ∀f ∈ Cc (Rk ).

Set JM (a) = HM,Π (ψδ )(a)

∀a ∈ UE .



Hence we get JM ∈ H (UE ) and f (ψa ) = JM (a)f˜(ψa ) M

∀a ∈ UE ∀f ∈ Cc (Rk ).

This proves the following corollary. Corollary ◦2. Let E be a Banach space of functions on Rk satisfying (H1), (H2) and (H3). k = ∅. Then, for M ∈ M(E), there exists J ∈ H∞ (U ) such that Suppose that R M E E f (ψa ) = JM (a)f˜(ψa ) M

∀a ∈ UE ∀f ∈ Cc (Rk ).

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MULTIPLIERS ON BANACH SPACES

Now we will give some examples of Banach spaces satisfying our conditions. Example 4. Let ω be a continuous non-negative real function on G. For 1  p < +∞ set Lpω (G) the space of the measurable functions on G such that  |f (x)|p ω(x)p dx < +∞ G

and set



(1/p)

f ω,p =

|f (x)|p ω(x)p dx

for f ∈ Lpω (G).

G

Obviously, the Banach space Lpω (G) satisfies our hypotheses (H1) and (H3). Condition (H2) holds if and only if we have ω(x + y) < +∞ ω(y) y∈G

∀x ∈ G.

sup

(1.4)

For a complete study of the representation of the multipliers on L2ω (R) see [16]. For illustration, we will give one concrete example. Set ∀(n, k) ∈ Z2

ω(n, k) = emax(n,k)

and E = lω2 (Z2 ). In this case we have Sn,k  = max(en , ek ) and ρ(Sn,k ) = max(en , ek ). Here, 2 ≈ σ(S the set Z 1,0 , S0,1 ) and using Theorem 3 we get E 2 ≈ {(z , z ) ∈ C2 |1  |z |  e, Z 1 2 i E

i ∈ {1, 2}, |z1 ||z2 | = e}.

Notice, that σ(S1,0 , S0,1 ) = spec(S1,0 ) × spec(S0,1 ) and that the interior of σ(S1,0 , S0,1 ) is ◦ ◦ +  empty although spec(S1,0 ) = ∅ and spec(S0,1 ) = ∅. However, it is clear that Z2E has at least two elements. Example 5.

Let ω be a continuous weight on G. Set C0,ω (G) = {f ∈ C(G)|f ω ∈ C0 (G)}.

We equip C0,ω (G) with the norm f  = f ω∞ . It is clear that C0,ω (G) satisfies conditions (H1) and (H3) and if ω has the property 0 < sup x∈G

ω(x + y) < +∞ ω(x)

∀y ∈ G,

hypotheses (H2) holds in C0,ω (G). Example 6. Let A be a real-valued continuous function on [0, +∞[, such that A(0) = 0 and let (A(y)/y) be non-decreasing for y > 0. Let LA (G) be the set of all complex-valued, measurable functions on G such that    |f (x)| dx < +∞ A t G for some positive number t and let







f A = inf t > 0|

A G

|f (x)| t



dx  1

for f ∈ LA (G). Then LA (G) is a Banach space called a Birnbaum–Orlicz space [3]. It is easy to check that LA (G) satisfies (H1), (H2) and (H3).

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V. PETKOVA

 2. The set G E Notice that for every φ ∈ CK (G), g ∈ E, the function G x −→ φ(x)Sx g ∈ E is uniformly continuous on G and  φ(x)Sx g dx  φ∞ g sup Sx m(K) < +∞. 

x∈K

K

We conclude that K φ(x)Sx g dx is well defined as a Bochner integral with respect to the strong operator topology [11, Chapter 3]. We have  Mφ = φ(x)Sx dx. (2.1) G

Indeed let K be a compact subset of G. We have Mφ (CK (G)) ⊂ CK+supp(φ) (G) and the restriction of G φ(x)Sx dx to CK (G) can be considered as a Bochner integral on CK (G) with values in CK+supp(φ) (G). It is clear that for x ∈ G, the map f −→ f (x) is a continuous linear form on CK0 , for every compact K0 . Since Bochner integrals commute with continuous linear forms we obtain, for g ∈ Cc (G),   Mφ g(x) = (φ ∗ g)(x) = φ(y)g(x − y) dy = φ(y)(Sy g)(x) dy G supp(φ)   =

φ(y)Sy g (x)

∀x ∈ G

supp(φ)

and formula (2.1) follows from the density of Cc (G) in E. Let A(E) be the closure in M(E) of the algebra {Mφ }φ∈Cc (G) . We have the following proposition. Proposition 1. If f ∈ Cc (G), f  0, f = 0, then we have ρ(Mf ) > 0. Proof. Fix f ∈ Cc (G) such that f  0 and f = 0. Let V be a compact neighbourhood of 0 such that supp(f ) ⊂ V and let F be a finite subset of G such that V + V ⊂ F + V . We set nV := {s1 + · · · + sn , s1 , . . . , sn ∈ V } and we notice that Denote f 1 =

 G

nV ⊂ (n − 1)F + V f (x) dx. We get 

∀n  1.

f ∗n (x) dx = f n1

(2.2)

∀n  1,

nV

where f ∗n is the product of n times f in the convolution algebra L1 (G). From (2.2) it follows that   ∗n f (x) dx = f ∗n (x) dx nV (n−1)F +V   = S−s f ∗n (x) dx s∈(n−1)F

 CV



V

s∈(n−1)F

S−s f ∗n E ,

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MULTIPLIERS ON BANACH SPACES

where CV is a constant such that  |g(x)| dx  CV gE

∀g ∈ E.

V

Let k be the number of the elements of F and let D = maxs∈F S−s . Then we have  S−s   k n−1 Dn−1 s∈(n−1)F

and consequently  n+1 f ∗(n+1) (x) dx  CV k n Dn f ∗(n+1)   CV k n Dn (Mf )n f  f 1 =

∀n  1.

G

We deduce that (Mf )n  

f n+1 1 CV f (kD)n

and therefore we get ρ(Mf ) 

f 1 > 0. kD

Observe that the proposition above implies that the algebra A(E) is not radical. Next notice that Sx ◦ Mφ = MSx (φ) , hence R ◦ T ∈ A(E) for each R ∈ B(E) and for each T ∈ A(E). Let  We have γ ∈ A(E). γ(R ◦ T2 ) γ(R ◦ T1 ) = γ(T1 ) γ(T2 ) / Ker(γ), and for R ∈ B(E), T1 , T2 ∈ A(E) \ Ker(γ). Now choose φ ∈ Cc (G) such that Mφ ∈ define Δγ : B(E) −→ C by the formula Δγ (R) =

γ(R ◦ Mφ ) γ(Mφ )

∀R ∈ B(E).

(2.3)

It is clear that Δγ (R1 ◦ R2 ) =

γ(R1 ◦ R2 ◦ Mφ2 ) γ(R1 ◦ R2 ◦ Mφ ) = = Δγ (R1 )Δγ (R2 ) γ(Mφ ) γ(Mφ2 )

 Notice that we have for R1 , R2 ∈ B(E). Since Δγ (I) = 1, we obtain Δγ ∈ B(E). 1  |Δγ (Sx )|  ρ(Sx ) ρ(S−x )

∀x ∈ G.

(2.4)

We need the following lemma. Lemma 1. Let E be a Banach space satisfying (H1) and (H2).   (i) For θ ∈ G E there exists γθ ∈ A(E) such that θ(x) =

γθ (Mφ ) γθ (Sx ◦ Mφ )

for φ ∈ Cc (G) such that Mφ ∈ / Ker(γθ ) and we have 1  |θ(x)−1 |  ρ(Sx ) ρ(S−x )

∀x ∈ G.

(2.5)

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V. PETKOVA

  (ii) The map T : θ −→ γθ is a homeomorphism from G E onto A(E), with respect to the Gelfand topology.  Proof. Fix θ ∈ G E and define



φ(x)θ(x)−1 dx

γθ (Mφ ) =

∀φ ∈ Cc (G).

(2.6)

G

 We will prove that Taking into account the Fubini theorem, it is easy to see that γθ ∈ A(E). θ(x) = We have, for y ∈ G, γθ (MSy φ ) =

 G

=

γθ (Mφ ) . γθ (Sx ◦ Mφ )

(2.7)



φ(x − y)θ(x)−1 dx  φ(x)θ(x + y)−1 dx = θ(y)−1 φ(x)θ(x)−1 dx = θ(y)−1 γθ (Mφ ) Sy φ(x)θ(x)

−1

dx =

G

G

G

and (2.7) holds. Next observe that (2.4) implies (2.5). This completes the proof of assertion (i).  and fix ψ ∈ Cc (G) such that Mψ ∈ Fix γ ∈ A(E) / Ker(γ). Set θγ (x) =

γ(Mψ ) γ(Sx ◦ Mψ )

∀x ∈ G.

Suppose that (φn )n0 ⊂ CK (G) is a sequence converging to φ ∈ CK (G) uniformly on K. For every g ∈ E we get Mφn g − Mφ g  φn − φ∞ sup Sy gm(K) y∈K

and this implies that limn→+∞ Mφn − Mφ  = 0. This shows that the linear map φ −→ Mφ is sequentially continuous and hence continuous from Cc (G) into A(E). Since the map x −→ Sx (φ) is continuous from G into Cc (G), we conclude that the map x −→ Sx ◦ Mφ = MSx (φ)  is continuous from G into A(E). Thus θγ is continuous on G. Now we will prove that θγ ∈ G E. Set η : Cc (G) φ −→ γ(Mφ ). The map η is a continuous linear form on Cc (G) and hence there exists some measure μ [10, Chapter 3] such that  η(φ) = φ(x) dμ(x) ∀φ ∈ Cc (G). G

This implies that for every f , φ ∈ Cc (G) we have  γ(Mφ ◦ Mf ) = (φ ∗ f )(t) dμ(t)  G  = φ(x)f (t − x) dx dμ(t). G

G

Using the Fubini theorem, we obtain     γ(Mφ ◦ Mf ) = φ(x) f (t − x) dμ(t) dx = φ(x)γ(Sx ◦ Mf ) dx G

G

G

MULTIPLIERS ON BANACH SPACES

and



φ(x)θ(x)−1 dx

γ(Mφ ) =

∀φ ∈ Cc (G).

379

(2.8)

G

   Consequently, we conclude that  G φ(x)θ(x)−1 dx = |γ(Mφ )|  Mφ  and θγ ∈ G E . Define  −→ G,  R : A(E)  by the formula for γ ∈ A(E), R(γ)(x) =

γ(Mφ ) γ(Sx ◦ Mφ )

∀x ∈ G

 / Ker(γ). We have T R = RT = I. Let θ0 ∈ G for φ ∈ Cc (G) such that Mφ ∈ E . For fixed φ1 , . . . , φk ∈ Cc (G) and > 0 we have      −1 −1  θ(x) φi (x) dx <

sup  θ0 (x) φi (x) dx − i=1,...,k

G

G

 for every θ ∈ G E such that sup

|θ0 (x)−1 − θ(x)−1 |
0 such that |γα (Mf )|  δ, ∀α  β. We have R(γα )(x)−1 = ((γα (Sx ◦ Mf ))/(γα (Mf ))) and we obtain |(R(γα )(x))−1 − (R(γα )(y))−1 |  δ −1 γα Sx ◦ Mf − Sy ◦ Mf   δ −1 Sx ◦ Mf − Sy ◦ Mf  ∀x, y ∈ G, ∀α  β. Thus we deduce that the family (R(γα ))αβ is equicontinuous on G. Since (R(γα )) converges to R(γ) simply, (R(γα )) converges uniformly on every compact of G to R(γ). Consequently, R is continuous and the proof is complete. Proposition 2. Let G be a topological group and let φ : G → R be a unital morphism. Then φ is continuous if and only if φ is locally bounded. Proof. Every continuous morphism is clearly locally bounded. Now assume that φ is locally bounded and let U be a neighbourhood of the unit element 0G , and M > 0 such that φ(U ) ⊂ [−M, M ]. Let > 0, and let n  1 be such that M/n < . There exists a neighbourhood V of 0 such that nx ∈ U, so that n|φ(x)|  M for every x ∈ V. Hence |φ(x)| < for every x ∈ V, which shows that φ is continuous at 0 and hence continuous on G. Corollary 3. Let E ⊂ L1loc (G) be a Banach space satisfying hypotheses (H1) and (H2).  Then the map x −→ |χ(Sx )| is continuous on G. Let χ ∈ B(E). Proof. Let K = K −1 be a compact neighbourhood of 0. It follows from hypotheses (H2) that 1  M := supx∈K Sx  < +∞. For x ∈ K we have |χ(Sx )|  M,

|χ(Sx )|−1  M.

We obtain − log M  log |χ(Sx )|  log M

∀x ∈ K,

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V. PETKOVA

and it follows from Proposition 2 that the map x −→ log |χ(Sx )| is continuous on G. This completes the proof.  Next we will use (H3). Recall that this condition implies that G E has the following property:   χG E = GE

 ∀χ ∈ G.

It is well known that a Reinhardt domain X such that 0 ∈ X is monomially convex if and only if it is a logarithmically convex domain and contains the polydisc of radius Y(z), for every z ∈ X \ {0}. Recall that the definition of a Reinhardt domain and the definition of the map Y are given in Section 1. Moreover, a Reinhardt domain X such that 0 ∈ X is monomially convex if and only if X is the domain of convergence of a power series [14]. The following proof of Theorem 3 is related to analogous results for Reinhardt domains contained in C∗k .  Proof of Theorem 3. Taking into account Proposition 1 and Lemma 1, it is clear that G E   + + is not empty. First, we prove that GE is equicontinuous. Let γ ∈ GE . We have 1  γ(x)−1  ρ(Sx ) ρ(S−x )

∀x ∈ G.

Hence for a compact neighbourhood V0 of 0G , we have 1 C−V0

 γ(x)−1  CV0

∀x ∈ V0 ,

where CV0 = supx∈V0 ρ(Sx ) < +∞ and C−V0 = supx∈V0 ρ(S−x ) < +∞. Fix δ > 0. There exists n > 0 such that (CV0 )1/n − 1 < δ and 1 − (1/(C−V0 )1/n ) < δ. The map x −→ nx is continuous on G and there exists a neighbourhood Wδ of 0 such that nx ∈ V0 , for x ∈ Wδ . Then 1  γ(nx)−1  CV0 C−V0

∀x ∈ Wδ

and 1  γ(x)−1  (CV0 )1/n (C−V0 )1/n

∀x ∈ Wδ .

It follows that 1 − δ  γ(x)−1  1 + δ and hence γ(0)−1 − δ  γ(x)−1  γ(0)−1 + δ, for   + + is equicontinuous at 0 and so G is equicontinuous on G. x ∈ W . Now it is clear that G δ

E

E

is bounded for every x ∈ G and it follows from the We have seen that the set {θ(x)−1 }θ∈G  E  +   definition of GE that GE is closed in G with respect to the uniform convergence on every  + compact subset. A standard version of the Ascoli theorem [19] implies that G E is compact.   + + Next we will prove that GE is log-convex. Suppose that GE has at least two elements. Let η1  and η2 be in G E and assume that |η1 | = |η2 |. Set L = {z ∈ C | Im z ∈ [0, 1]}. For λ ∈ L, define θλ (x) = |η1 (x)|λ |η2 (x)|1−λ ,

x ∈ G.

For f ∈ Cc (G) and for every x ∈ supp(f ) we have  −1

sup |f (x)θλ (x) λ∈L

|  f ∞ sup l∈[0,1]

sup x∈supp(f )

 |η1 (x)|

l

sup

|η2 (x)|

1−l

< +∞.

x∈supp(f )

The function G × L : (x, λ) −→ f (x)θλ (x)−1 ∈ C is separately continuous and uniformly bounded and so this function is measurable on G × L [13]. Then using the Morera theorem and the Fubini theorem, we obtain that for f ∈ Cc (G)

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the function F defined by



f (x)θλ (x)−1 dx

F : λ −→ G ◦

is analytic on the strip L. By the Phragmen–Lindel¨ of theorem, we obtain     |F (λ)|  max  f (x)θλ (x)−1 dx  Mf . Re λ∈{0,1}

Then we have

G

      |η1 (x)|ia  |η2 (x)|ia    dx , sup f (x)|η1 (x)| dx . |F (λ)|  max sup  f (x)|η2 (x)| |η2 (x)|ia  a∈R  |η1 (x)|ia  a∈R 

G

G

 + ia 1−ia 1−ia   Since |η2 | ∈ G |η1 |ia ∈ G |η2 |ia ∈ E , ∀a ∈ R. Similarly |η1 | E and |η1 /η2 | ∈ G, we have |η2 |  G E ∀a ∈ R and we obtain |F (λ)|  Mf 

∀λ ∈ L.

 This implies that θλ ∈ G E ∀λ ∈ L.  +  + and suppose that θ ∈ Now we prove (ii). Let θ ∈ G /G E . Then there exists φ ∈ Cc (G) and

> 0 such that      φ(x)θ(x)−1 dx > Mφ  + . (2.9)   G

 + Let K = supp(φ). Since the family {φη −1 , η ∈ G E ∪ {θ}} is equicontinuous on K, for every x ∈ K there exists a neighbourhood Vx of x in K such that

 + ∀η ∈ G sup |φ(y)η(y)−1 − φ(x)η(x)−1 | < E ∪ {θ}. 3m(K) y∈Vx The family {Vx }x∈K is an open covering of K, hence there exists a1 , . . . , ap ∈K such that p K ⊂ i=1 Vai . Set Vaci = {x ∈ K | x ∈ / Vai }. Define K1 = Va1 and Ki = Vai ∩ ( j =i Vaj )c for 1 < i  p. We see that   p      −1 −1 φ(ai )η(ai ) m(Ki )  φ(x)η(x) dx −  K  i=1   p      (φ(x)η(x)−1 − φ(ai )η(ai )−1 ) dx =   i=1 Ki  p p  



m(Ki ) = .  dx = 3m(K) 3m(K) i=1 3 i=1 Ki  + Let η ∈ G E . Since we have   p      φ(ai )η(ai )−1 m(Ki )   φ(x)η(x)−1 dx −   K i=1   p      φ(ai )θ(ai )−1 m(Ki )   φ(x)θ(x)−1 dx −   K i=1

and

     −1  φ(x)η(x)−1 dx −  > , φ(x)θ(x) dx   K

K

, 3

3

382

V. PETKOVA

we obtain

 p  p   

  −1 −1 φ(ai )η(ai ) m(Ki ) − φ(ai )θ(ai ) m(Ki ) > .    3 i=1 i=1

Hence we get  + ∀η ∈ G E.

(θ(a1 )−1 , . . . , θ(ap )−1 ) = (η(a1 )−1 , . . . , η(ap )−1 ) Set

C = (log |η(a1 )|, . . . , log |η(ap )|),

  η∈G E .

Since the set C is closed and convex, we have (log θ(a1 ), . . . , log θ(ap )) ∈ / C. Hence, there exists a linear form L on Rp such that L ((log θ(a1 ), . . . , log θ(ap ))) > sup L ((log |η(a1 )|, . . . , log |η(ap )|)) .  η∈G E

Set

⎧ ⎨ Δ = (α1 , . . . , αp ) ∈ Rp |α1 log θ(a1 ) + · · · + αp log θ(ap ) ⎩ ⎫ ⎬ > sup (α1 log η(a1 ) + · · · + αp log η(ap )) . ⎭  + η∈GE

Since sup

 η∈G+ E

| log η(ai )| < +∞ for 1  i  p, Δ is open, and since λΔ ⊂ Δ for λ > 0 we have

Δ ∩ Z = ∅. Now let (n1 , . . . , np ) ∈ Δ ∩ Zp . We have p

1 1 p −1 p −1 θ(a−n . . . a−n ) > sup |η(a−n . . . a−n ) | p p 1 1

 η∈G E

and this shows that





 | |θ(x)−1 |  sup |η(x)−1 | θ∈G  η∈G E

∀x ∈ G

 ⊂G E,

which proves (ii). Corollary 4.

We have −1   |  ρA(E) (Sx ) G E = {θ ∈ G | |θ(x)

∀x ∈ G},

where ρA(E) (Sx ) = supγ∈A(E)  |Δγ (Sx )|. We recall that the definition of Δγ is given by formula (2.3). Corollary 5.

  G E is connected if and only if G is connected.

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MULTIPLIERS ON BANACH SPACES

3. A representation theorem 3.1. Quasimeasures In this section we give some useful results about the representation of a multiplier as a convolution operator. Let BG be the family of Borel of G. A measure on G is a map μ : BG,μ −→ C of the form μ = μ1 − μ2 + iμ3 − iμ4 , where μi is a positive measure on G for i = 1, . . . , 4 such that μi (K) < +∞, for every K compact subset of G and where BG,μ = {U ∈ BG | sup μi (U ) < +∞, i = 1, . . . , 4}. Denote by M (G) the set of the measures on G. The Riesz representation theorem shows that every continuous linear form on Cc (G) can be uniquely represented in the form  L(f ) = G f (x) dμL (x), where μL ∈ M (G). We will denote by Mb (G) the set of all measures on G of bounded variations, equipped with the norm μMb (G) = |μ|(G), which can be identified as above with the dual of C0 (G). Denote by Mc (G) the set of measures on G with compact support and equip M (G) with the vague topology. Recall that a net (μα ) ⊂ M (G) converges vaguely to μ ∈ M (G) if and only if   f (x) dμ(x) = lim f (x) dμα (x) ∀f ∈ Cc (G). α

G

G

We need the following definitions in order to introduce the result of Gaudy proved in [9]. Definition 2. DK (G) =

Let K be a compact subset of G. Define

u ∈ Cc (G)|u =

∞ 

fi ∗ gi , fi , gi ∈ CK (G)

and

i=1

∞ 

fi ∞ gi ∞ < +∞ .

i=1

We equip DK (G) with the norm ∞ ∞   uDK (G) = inf fi ∞ gi ∞ | u = fi ∗ gi , fi , gi ∈ CK (G) i=1

and

i=1 ∞ 



fi ∞ gi ∞ < +∞ .

i=1

Definition 3. Consider in the category of locally convex spaces the inductive limit D(G) = limDK (G). Denote by D(G) the dual space of D(G). The elements of D(G) are → called quasimeasures. We have the following important result. Theorem 5 [9]. For every continuous linear operator M from Cc (G) into the space of measures M (G), which commutes with convolutions by functions in Cc (G), there exists a quasimeasure μ such that M f = μ ∗ f ∀f ∈ Cc (G). Notice that for all f ∈ Cc (G) the application g −→ f ∗ g is continuous from D(G) into D(G) and for f ∈ Cc (G), μ ∗ f is a quasimeasure defined by μ ∗ f, g = μ, f ∗ g

∀g ∈ D(G).

384

V. PETKOVA

If f ∈ D(G), then μ ∗ f is a continuous function on G defined by: y −→ μx , f (x − y). Applying Theorem 5, the restriction to Cc (G) of a multiplier on Lp (G), for 1  p < +∞, is characterized as a convolution with a quasimeasure [9, 2]. Otherwise, Edwards gave a representation theorem for multipliers from Cc (G) into Mc (G). Set  B(G) = {fˆ, f ∈ L1 (G)} and fˆB(G) = f L1 (G)  . We will denote by P (G) the dual of B(G). The elements of P (G) are called pseudomeasures. Denote by P 1 (G) the set of all pseudomeasures s such that s ∗ f ∈ Mb (G) for all f ∈ Cc (G). We have the following theorem. Theorem 6 [7]. (1) The continuous linear operators T from Cc (G) into Mb (G) which commute with translations are precisely the operators having the form Tf = s ∗ f

∀f ∈ Cc (G),

where s ∈ P (G). (2) The continuous linear operators T from Cc (G) into Mc (G) which commute with translations are precisely the operators having the form 1

Tf = s ∗ f

∀f ∈ Cc (G),

where s is a pseudomeasure with compact support. Furthermore, this theorem implies that a quasimeasure with compact support is a pseudomeasure [9]. The Fourier transform sˆ of a pseudomeasure s is defined as follows: sˆ is the continuous linear form on L1 (G) given by sˆ : L1 (G) f −→ s(fˆ) ∈ C.  Following Theorem 6, for a linear Notice that sˆ can be identified with an element of L∞ (G). operator T from Cc (G) into Mb (G) continuous with respect to the inductive limit topology on Cc (G) and the vague topology on M (G) and commuting with convolutions by functions in Cc (G) we have (3.1) Tf = hfˆ ∀f ∈ Cc (G),  Such a representation holds also for multipliers on Lp (G), 1  p < +∞ where h ∈ L∞ (G). (see [2]). 3.2. Approximation of a multiplier We need several lemmas. If E ⊂ L1loc (G) is a Banach space satisfying (H1), (H2) and (H3) we will denote as before by Mφ : f −→ f ∗ φ the convolution operator associated with a function φ ∈ Cc (G). Following some arguments of Gaudry and Figa-Talamanca [8, 9], we obtain the following. Lemma 2. Let E ⊂ L1loc (G) be a Banach space satisfying (H1), (H2) and (H3). For every M ∈ M(E) there exists a net (φα ) ⊂ Cc (G) such that (i) M = limα Mφα with respect to the strong operator topology; (ii) we have Mφα   CM , where C is a constant independent of M.

385

MULTIPLIERS ON BANACH SPACES

Proof. Fix M ∈ M(E). Let μ be the quasimeasure such that Mf = μ ∗ f

∀f ∈ Cc (G).

 −→ E by Fix f ∈ E and define Tf : G Tf (χ) = χM (χf ),

 χ ∈ G.

 into E. Denote by 1  the unit element of G.  It is easy to see that Tf is continuous from G G 1  Let (kα ) ⊂ L (G) be a net such that k α ∈ Cc (G), kα L1 (G)  = 1, kα (χ)  0, for every α and  limα χ∈V kα (χ) dχ = 0, for every neighbourhood V of 1G . We have / lim(kα ∗ Tf )(1G ) = Tf (1G ) = M f, α

Observe that



−1

 G

kα (χ)χ

and it shows that

−1

M (χ

 f )dχ 

  G

 G

∀f ∈ E.

kα (χ)M χ−1 f dχ  M f 

(3.2)

kα (χ)χ−1 M (χ−1 f ) dχ

 with values in E. Define Yα : E −→ E by the formula is well defined as a Bochner integral on G  Yα (f ) = (kα ∗ Tf )(1G ) = kα (χ)χ−1 M (χ−1 f ) dχ.  G

We claim that for f ∈ DK (G) and x ∈ G, we have  Yα f (x) = kα (χ)χ(x)−1 M (χ−1 f )(x) dχ.  G

(3.3)

We will justify formula (3.3). First, we will show that if f ∈ DK (G) then M (f χ−1 ) is continuous on G. Indeed, we have M (χ−1 f )(x) = μy , χ(y − x)−1 f (y − x)

∀x ∈ G.

Notice that for g ∈ DK (G), for x0 ∈ G and a compact K0 which contains both K and K + Vx0 , where Vx0 is a neighbourhood of x0 , we get Sx g − Sx0 gDK0 (G)

    inf Sx fi − Sx0 fi ∞ gi ∞ , s.t. g = fi ∗ gi , fi ∞ gi ∞ < +∞ . i

i

i

It is clear that lim Sx fi − Sx0 fi ∞ = 0

x→x0

for every i and since



fi ∞ gi ∞ < +∞

i

we obtain lim Sx g − Sx0 gDK0 (G) = 0.

x→x0

It follows that the function M (χ−1 f ) is continuous. Secondly we need the bound sup sup |M (f χ−1 )(x)| < +∞.

 x∈G χ∈G

(3.4)

386

V. PETKOVA

Let Sx DK (G)→DK0 (G) be the norm of the operator Sx considered as an operator on DK (G)  we obtain into DK0 (G). Then, for χ ∈ G, (M (χ−1 f ))(x0 ) = μy , f (y − x0 )χ(y − x0 )−1   μSx0 DK (G)→DK0 (G) f χ−1 DK (G) . It is easy to see that f χ−1 DK (G) = f DK (G) and hence Sx0 DK (G)→DK0 (G)  1. This implies sup |M (f χ−1 )(x0 )| < μf 

 χ∈G

and (3.4). Let x0 ∈ G and let K0 be a compact neighbourhood of x0 . Let ψ ∈ CK0 (G) be such that ψ(x0 ) = 1. Clearly,   −1 −1 kα (χ)ψχ M (χ f )∞ dχ  A kα (χ) dχ,  G

 G

where A is a constant. Consequently,  kα (χ)ψχ−1 M (χ−1 f ) dχ  G

is well defined as a Bochner integral with values in CK0 (G). Therefore, since ψχ−1 M (χ−1 f ) ∈ CK0 (G), repeating the argument of the beginning of Section 2, we obtain    kα (χ)ψχ−1 M (χ−1 f ) dχ (x) = kα (χ)ψ(x)χ(x)−1 M (χ−1 f )(x) dχ ∀x ∈ K0 ,  G

 G

which implies that    −1 −1 kα (χ)χ M (χ f ) dχ (x0 ) = kα (χ)χ(x0 )−1 M (χ−1 f )(x0 ) dχ.  G

 G

 of kα (χ)ψχ−1 M (χ−1 f ) Taking into account condition (H1), the Bochner integral on G considered with respect to the norm of E defines the same function as the Bochner integral on  of kα (χ)ψχ−1 M (χ−1 f ) considered with respect to the norm of CK (G) and this completes G 0 the proof of (3.3). Now, for f ∈ D(G) and x ∈ G, we have  kα (χ)χ(x)−1 M (χ−1 f )(x) dχ Yα f (x) =  G  = kα (χ)χ(x)−1 μy , (χ−1 f )(y − x)dχ  G = kα (χ)μy , χ(−y)f (y − x)dχ  G    = μy , kα (χ)χ(−y) dχ f (y − x)  G

 = μy , k α (y)f (y − x) = (kα μ ∗ f )(x). Moreover, taking into account (3.2), we have a control of the norm of the operator Yα . Indeed, we have Yα   M . To approximate M with respect to the strong operator topology, it is sufficient to approximate the operators Yα , which are the convolutions with the quasimeasures  with compact support k α μ. In order to do this we fix α and we set ν = kα μ. Recall that ν

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MULTIPLIERS ON BANACH SPACES

is also a pseudomeasure. Denote by V the operator of convolution with ν. Consider a net (hβ ) ⊂ Cc (G) ∗ Cc (G) satisfying the following conditions: (i) hβ L1 (G) = 1 ∀β; (ii) hβ vanishes outside some fixed compact K; (iii) hβ (x)  0 ∀x ∈ G;  hβ (x)dx = 0. (iv) For every neighbourhood O of 0G , limβ x∈O / Set Vβ (f ) = V (hβ ∗ f ), for f ∈ E. Taking into account our hypotheses on E and the properties of (hβ ), it is easy to see that limβ hβ ∗ f − f  = 0 ∀f ∈ E. It implies that limβ Vβ f − V f  = 0 for f ∈ E. Moreover, it is easy to control the norm of Vβ . In fact, for f ∈ Cc (G), we have Vβ f = V f ∗ hβ and      Vβ f  = hβ ∗ V f  =  hβ (y)Sy (V f )dy   G   |hβ (y)|Sy (V f ) dy  (sup Sy )V f . y∈K

G

Hence we obtain Vβ   CV , where C is a constant. On the other hand, Vβ f = (ν ∗ hβ ) ∗ f for f ∈ Cc (G). For g ∈ D(G) we have    ν ∗ hβ , g = ν, g ∗ hβ  = νx , (Sy hβ )(x)g(y) dy . G

We recall that ν ∈ P (G) and Sy hβ ∈ Cc (G) ∗ Cc (G). It is easy to see that Cc (G) ∗ Cc (G) ⊂  we have B(G). Indeed, for f1 , f2 ∈ Cc (G), f1 ∗ f2 = F −1 (Ff1 Ff2 ) and since Ff1 , Ff2 ∈ L2 (G), 1  Ff1 Ff2 ∈ L (G). Observe that   Sy hβ B(G) |g(y)| dy = hβ B(G) |g(y)| dy < +∞ G

G

 and hence G g(y)Sy hβ dy is a Bochner integral with values in B(G). Since Bochner integrals commute with continuous linear forms, we have  ν ∗ hβ , g = νx , (Sy hβ )(x)g(y)dy ∀g ∈ D(G). G

We deduce that the quasimeasure ν ∗ hβ is the function defined by (ν ∗ hβ )(y) = νx , hβ (x − y) = ν, Sy hβ  We will check that the function G : G y −→



 χ −→ G

∀y ∈ G. 

 (Sy hβ )(x)χ(x) dx

 ∈ L1 (G)

G

 We have is continuous from G into L (G). 1

β (χ−1 ) G(y) : χ −→ χ(y)h  the function for all y ∈ G. It is easy to see that for φ ∈ Cc (G)    χ −→ χ(y)φ(χ) ∈ L1 (G) G y −→ G  is dense in L1 (G),  we obtain that G is the uniform limit of is continuous. Indeed, since Cc (G) a sequence of continuous functions and hence G is continuous. We conclude that the function G y −→ Sy hβ ∈ B(G) is continuous from G into B(G). We deduce that ν ∗ hβ ∈ Cc (G) and the proof is complete. Now we are ready to prove our main theorem.

388

V. PETKOVA

 Proof of Theorem 4. Fix M ∈ M(E) and θ ∈ G E . Let (φα ) ⊂ Cc (G) be a net such that (Mφα ) converges to M with respect to the strong operator topology and such that Mφα    CM . Fix θ ∈ G E . We have         φα θ−1 (χ) =  φα (x)θ(x)−1 χ(x)−1 dx  Mφα   CM  ∀χ ∈ G. G

−1 ) converges to a function h If we replace (φα ) by a suitable subnet, we obtain that (φ αθ M,θ ∈ ∞  ∗ ∞  1  L (G) for the weak topology σ(L (G), L (G)). Moreover, we have hM,θ ∞  CM . Taking into account that   −1 (χ)g(χ) dχ =  lim φ θ hM,θ (χ)g(χ) dχ ∀g ∈ L1 (G), α α

 G

 G

we obtain   −1 (χ)f −1 (χ)g(χ) dχ =  lim φ θ θ hM,θ (χ)f θ−1 (χ)g(χ) dχ α α

 G

 G

 ∀f ∈ Cc (G), ∀g ∈ L2 (G).

This implies that for each f ∈ Cc (G), the net (F((Mφα f )θ−1 )) = (F((φα ∗ f )θ−1 )) = −1 f   Consequently, (φ θ−1 ) converges to hM,θ f θ−1 with respect to the weak topology of L2 (G). αθ θ−1 ) lim(Mφα f )θ−1 = F −1 (hM,θ f α

∀f ∈ Cc (G)

with respect to the weak topology of L2 (G). On the other hand, lim Mφα f − M f  = 0 α

∀f ∈ E

and by (H1), for g ∈ Cc (G), we get     −1  lim  g(y)θ(y) (Mφα f (y) − M f (y))dy  = 0. α G

θ−1 ) define the same linear functional on Cc (G) We see that functions (M f )θ−1 and F −1 (hM,θ f for every f ∈ Cc (G). We obtain for all f ∈ Cc (G), θ−1 )(x), a.e. (M f )(x)θ(x)−1 = F −1 (hM,θ f  we have θ−1 ) ∈ L2 (G). Then, for almost every χ ∈ G, Notice that (M f )θ−1 = F −1 (hM,θ f F((M f )θ−1 )(χ) = hM,θ (χ)F(f θ−1 )(χ)

∀f ∈ Cc (G).

 +  We set for M ∈ M(E), for δ ∈ G E and for almost every χ ∈ G hM (δχ) = hM,δ (χ).  +  Then, for every δ ∈ G E and for almost every χ ∈ G we have f (δχ) = hM (δχ)f˜(δχ) M

∀f ∈ Cc (G),

 f (δχ) = (M where M f )δ −1 (χ) a.e. This completes the proof of (i).  Now we will prove assertion (ii). Let U be an open subset of Cp and let Π : U −→ G E be an  , we have analytic function. Since for every λ ∈ U , Π(λ) ∈ G E   −1   sup (Π(λ)(x))  sup ρ(Sx )  sup Sx  < +∞ x∈K

x∈K

x∈K

 the function for every compact K ⊂ G. For χ ∈ G, −1

G × U (x, λ) −→ φα (x) (Π(λ)(x))

χ(x)−1

is separately continuous and uniformly bounded and so is a measurable function on G × U (see [13]). Let D1 , . . . , Dp be open discs of C such that D1 × · · · × Dp ⊂ U . For fixed λj , for

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MULTIPLIERS ON BANACH SPACES

j = i and for every triangle T ⊂ Di , using the Fubini theorem, we have   φα (x)(Π(λ1 , . . . , λp )(x))−1 χ(x)−1 dλi dx T G    = φα (x)χ(x)−1 (Π(λ1 , . . . , λp )(x))−1 dλi dx. G

T −1

Since λi −→ (Π(λ1 , . . . , λp )(x)) function

is analytic on Ui , we obtain by the Morera theorem that the 

φα (x)(Π(λ1 , . . . , λp )(x))−1 χ(−x) dx

Di λi −→ G

is analytic. We obtain that −1

U λ −→ F(φα Π(λ)



φα (x)(Π(λ)(x))−1 χ(−x) dx

)(χ) = G

is separately analytic, hence analytic on U . Set α (Π(·)χ) ∈ H∞ (U ).  χ −→ φ Δα : G For every α we have Δα L∞ (G,H  ∞ (U ))  CMφα .  H∞ (U )) is uniformly bounded. Equip U with the Lebesgue measure. The net (Δα ) ⊂ L∞ (G, We can identify the dual of L1 (U ) with L∞ (U ), the duality being implemented by the formula  f, g = f (x)g(x) dx ∀f ∈ L1 (U ) ∀g ∈ L∞ (U ). U ∞

The space H (U ) is closed with respect to the topology σ(L∞ (U ), L1 (U )). Set ∞ H⊥ (U ) = {f ∈ L1 (U )|f, g = 0

∀g ∈ H∞ (U )}.

∞ We can identify the dual of H∗∞ (U ) := L1 (U )/H⊥ (U ) with H∞ (U ). We set

P(f ), g = f, g

∀f ∈ L1 (U ) ∀g ∈ H∗∞ (U ),

∞  with the where P : L1 (U ) −→ L1 (U )/H⊥ (U ) denotes the canonical surjection. Now, equip G  H∞ (U )) with L∞ (G,  H∞ (U )), the duality being Haar measure and identify the dual of L1 (G, ∗ implemented by the formula   H∞ (U )) ∀g ∈ L∞ (G,  H∞ (U )). f, g = f (χ), g(χ)dχ ∀f ∈ L1 (G, ∗  G

 H∞ (U )) with We can extract from (Δα ) a subnet convergent to a function HM,Π ∈ L∞ (G, ∗ ∞  ∞ 1  ∞ respect to the weak topology σ(L (G, H (U )), L (G, H∗ (U ))). We will denote also by (Δα ) this convergent subnet. We have    H∞ (U )). lim g(χ)(·), Δα (χ)(·)dχ = g(χ)(·), HM,Π (χ)(·)dχ ∀g ∈ L1 (G, ∗ α

 G

 G

 Set Lλ : H (U ) F −→ F (λ), for λ ∈ U . Notice that Lλ ∈ H∗∞ (U ), for λ ∈ U . Fix g ∈ L1 (G)  H∞ (U )) by the formula G(χ)(λ) = g(χ)Lλ for every λ ∈ U , for almost and define G ∈ L1 (G, ∗  For almost every χ ∈ G  we have every χ ∈ G. ∞

G(χ)(·), Δα (χ)(·) = g(χ)Δα (χ)(λ)

∀λ ∈ U

and G(χ)(·), HM,Π (χ)(·) = g(χ)HM,Π (χ)(λ)

∀λ ∈ U.

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MULTIPLIERS ON BANACH SPACES

It follows that

 lim α

 G

α (Π(λ)χ) dχ = g(χ)φ

  G

g(χ)HM,Π (χ)(λ) dχ

∀λ ∈ U.

 Using the definition of hM given in the proof of (i), we conclude that for almost every χ ∈ G HM,Π (χ)(λ) = hM (Π(λ)χ)

∀λ ∈ U.

 we obtain Finally, for all λ ∈ U and for almost all χ ∈ G, f (Π(λ)χ) = HM (χ)(λ)f˜(Π(λ)χ) M Acknowledgement. ment.

∀f ∈ Cc (G).

The author thanks Jean Esterle for his useful advice and encourage-

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Violeta Petkova Laboratoire Bordelais d’Analyse et G´eom´etrie UMR 5467 Universit´e Bordeaux 1 351, cours de la Lib´eration 33405 Talence France [email protected]