Bank savings, solution 1º) C0 = 5000

Bank savings, solution. 1º) C0 = 5,000 $ ;. C1=5,000×(1+. 2.5. 100)+1,000=6,125 $. ;. C2=6,125×(1+. 2.5. 100)+1,000=7,278.125 $. 2º) Cn+1=(1+. 2.5.
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Bank savings, solution 1º) C0 = 5,000 $ ;

(

C 1=5,000× 1+

)

2.5 +1,000=6,125 $ 100

(

2º) C n +1= 1+

;

(

C 2=6,125× 1+

)

2.5 +1,000=7,278.125 $ 100

)

2.5 C +1,000=1.025C n +1,000 . 100 n

This sequence is neither arithmetic, nor geometric, because from one term to the next, we not only multiply by 1.025, but we also add 1,000 $. 3º) t n =C n +40,000 . a) To prove that the sequence (tn) is geometric, we calculate

t n+1 tn

and we try to prove that it is a constant. t n+1 C n+1 +40,000 1.025C n +1,000+40,000 1.025 C n +41,000 1.025(C n +40,000) = = = = =1.025 tn C n +40,000 C n+40,000 C n +40,000 (C n +40,000)

therefore the sequence (tn) is geometric and its ratio is 1. 025. b) t n =t 0 ×q n =(5,000+40,000)×1.025n=45,000×1.025n . C n =t n −40,000=45,000×1.025n−40,000 On the 1 st of january 2021, C 10=45,000×1.02510 −40,000≈17,603.80 $ .